QUESTION IMAGE
Question
name:
date:
worksheet #2 - calculating protons, electrons, and neutrons
element
symbol
atomic
number
atomic mass
protons
electrons
neutrons
h
1
1
2
2
li
7
be
4
9
5
5
6
c
12
7
14
o
16
8
f
9
ne
20
11
23
12
12
al
14
15
31
32
cl
17
ar
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Step1: Proton and Electron Relationship
For a neutral atom, the number of protons is equal to the atomic number, and the number of electrons is equal to the number of protons.
Step2: Neutron Calculation
The number of neutrons is calculated as \( \text{Neutrons}=\text{Atomic Mass}-\text{Atomic Number}\)
For \(H\):
- Protons \( = 1\) (atomic number)
- Electrons \(=1\) (since it's neutral)
- Neutrons \(=1 - 1=0\)
For the element with atomic number \(2\):
- Symbol is \(He\)
- Protons \(=2\)
- Electrons \(=2\)
- Atomic Mass \(=2 + 2=4\)
For \(Li\):
- Atomic number \(=3\) (from periodic table, \(Li\) is the 3rd element)
- Protons \(=3\)
- Electrons \(=3\)
- Neutrons \(=7 - 3=4\)
For \(Be\):
- Protons \(=4\) (atomic number)
- Electrons \(=4\)
For the element with atomic number \(5\):
- Symbol is \(B\)
- Protons \(=5\)
- Electrons \(=5\)
- Atomic Mass \(=5 + 6=11\)
For \(C\):
- Atomic number \(=6\)
- Protons \(=6\)
- Electrons \(=6\)
- Neutrons \(=12 - 6=6\)
For the element with atomic number \(7\):
- Symbol is \(N\)
- Protons \(=7\)
- Electrons \(=7\)
- Neutrons \(=14 - 7=7\)
For \(O\):
- Atomic number \(=8\)
- Protons \(=8\)
- Electrons \(=8\)
For \(F\):
- Atomic Mass \(=9 + 10=19\) (since neutrons \(=10\) as \(19-9 = 10\))
- Protons \(=9\)
- Electrons \(=9\)
For \(Ne\):
- Atomic number \(=10\)
- Protons \(=10\)
- Electrons \(=10\)
- Neutrons \(=20 - 10=10\)
For the element with atomic number \(11\):
- Symbol is \(Na\)
- Protons \(=11\)
- Electrons \(=11\)
- Neutrons \(=23 - 11=12\)
For the element with protons \(12\):
- Atomic number \(=12\) (symbol \(Mg\))
- Electrons \(=12\)
- Atomic Mass \(=12 + 12=24\)
For \(Al\):
- Atomic number \(=13\)
- Protons \(=13\)
- Electrons \(=13\)
- Atomic Mass \(=27\) (common isotope), neutrons \(=27-13 = 14\)
For the element with atomic number \(14\):
- Symbol is \(Si\)
- Protons \(=14\)
- Electrons \(=14\)
- Atomic Mass (common isotope) \(=28\), neutrons \(=28 - 14=14\)
For the element with atomic number \(15\):
- Symbol is \(P\)
- Protons \(=15\)
- Electrons \(=15\)
- Neutrons \(=31 - 15=16\)
For the element with atomic mass \(32\):
- If we assume it's \(S\) (atomic number \(16\))
- Protons \(=16\)
- Electrons \(=16\)
- Neutrons \(=32 - 16=16\)
For \(Cl\):
- Atomic Mass (common isotope) \(=35\)
- Protons \(=17\)
- Electrons \(=17\)
- Neutrons \(=35 - 17=18\)
For \(Ar\):
- Atomic number \(=18\)
- Protons \(=18\)
- Electrons \(=18\)
- Atomic Mass (common isotope) \(=40\), neutrons \(=40 - 18=22\)
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| Element Symbol | Atomic Number | Atomic Mass | Protons | Electrons | Neutrons |
|---|---|---|---|---|---|
| \(He\) | \(2\) | \(4\) | \(2\) | \(2\) | \(2\) |
| \(Li\) | \(3\) | \(7\) | \(3\) | \(3\) | \(4\) |
| \(Be\) | \(4\) | \(9\) | \(4\) | \(4\) | \(5\) |
| \(B\) | \(5\) | \(11\) | \(5\) | \(5\) | \(6\) |
| \(C\) | \(6\) | \(12\) | \(6\) | \(6\) | \(6\) |
| \(N\) | \(7\) | \(14\) | \(7\) | \(7\) | \(7\) |
| \(O\) | \(8\) | \(16\) | \(8\) | \(8\) | \(8\) |
| \(F\) | \(9\) | \(19\) | \(9\) | \(9\) | \(10\) |
| \(Ne\) | \(10\) | \(20\) | \(10\) | \(10\) | \(10\) |
| \(Na\) | \(11\) | \(23\) | \(11\) | \(11\) | \(12\) |
| \(Mg\) | \(12\) | \(24\) | \(12\) | \(12\) | \(12\) |
| \(Al\) | \(13\) | \(27\) | \(13\) | \(13\) | \(14\) |
| \(Si\) | \(14\) | \(28\) | \(14\) | \(14\) | \(14\) |
| \(P\) | \(15\) | \(31\) | \(15\) | \(15\) | \(16\) |
| \(S\) | \(16\) | \(32\) | \(16\) | \(16\) | \(16\) |
| \(Cl\) | \(17\) | \(35\) | \(17\) | \(17\) | \(18\) |
| \(Ar\) | \(18\) | \(40\) | \(18\) | \(18\) | \(22\) |