QUESTION IMAGE
Question
name all the points shown that must be midpoints of the sides of the large triangle.
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\\(\overleftrightarrow{ae}\\), \\(\overleftrightarrow{bf}\\), \\(\overleftrightarrow{cg}\\), and \\(\overleftrightarrow{dh}\\) are parallel, with \\(ef = fg = gh\\). complete.
- if \\(ab = 5\\), then \\(ad = \underline{\\ ?\\ }\\).
- if \\(ac = 12\\), then \\(cd = \underline{\\ ?\\ }\\).
- if \\(ab = 5x\\) and \\(bc = 2x + 12\\), then \\(x = \underline{\\ ?\\ }\\).
- if \\(ac = 22 - x\\) and \\(bd = 3x - 22\\), then \\(x = \underline{\\ ?\\ }\\).
b 14. if \\(ab = 15\\), \\(bc = 2x - y\\), and \\(cd = x + y\\), then \\(x = \underline{\\ ?\\ }\\) and \\(y = \underline{\\ ?\\ }\\).
- if \\(ab = 12\\), \\(bc = 2x + 3y\\), and \\(bd = 8x\\), then \\(x = \underline{\\ ?\\ }\\) and \\(y = \underline{\\ ?\\ }\\).
Step1: Analyze the parallel lines and equal segments
Given that \(\overleftrightarrow{AE}\), \(\overleftrightarrow{BF}\), \(\overleftrightarrow{CG}\), and \(\overleftrightarrow{DH}\) are parallel, and \(EF = FG = GH\). By the Basic Proportionality Theorem (Thales' theorem) or the theorem of parallel lines cutting transversals proportionally, the segments on the transversal \(AD\) should be equal. Since there are three equal segments on the other transversal (\(EF, FG, GH\)), the transversal \(AD\) is divided into three equal parts as well. So \(AB = BC = CD\).
Step2: Solve for \(AD\) when \(AB = 5\)
Since \(AB = BC = CD = 5\) (from the proportionality of parallel lines), then \(AD=AB + BC+CD\). Substituting the values, we get \(AD = 5+5 + 5=15\).
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