Question

nahco₃ + hcl → nacl + h₂o + co₂
mm nahco₃ = 84.01 g/mol
you previously determined that a sealed container holds 0.0135 moles of co₂ gas. use stoichiometry to calculate the mass of nahco₃ needed to generate the 0.0135 mol co₂.
? g nahco₃

Explanation:

Step1: Find mole ratio of NaHCO₃ to CO₂

From balanced equation: 1 mol NaHCO₃ → 1 mol CO₂, ratio = 1:1

Step2: Calculate moles of NaHCO₃

Moles NaHCO₃ = moles CO₂ = 0.0135 mol

Step3: Compute mass of NaHCO₃

Mass = moles × molar mass = 0.0135 mol × 84.01 g/mol = 1.134135 g

Answer:

1.13 (rounded to two decimal places) or 1.134 g (unrounded)