Question

na (aq) + oh (aq) + h (aq) + cl (aq) → na (aq) + cl (aq) + h₂o(l)
part 3 of 4
are there any spectator ions in this reaction?
yes
no
part: 3 / 4
part 4 of 4
if you said there are spectator ions in this reaction write the net ionic equation, otherwise write na in the box below.

Explanation:

Spectator ions are ions that are present in the reaction mixture but do not participate in the actual chemical reaction. In the given equation \(Na^{+}(aq)+OH^{-}(aq)+H^{+}(aq)+Cl^{-}(aq)\to Na^{+}(aq)+Cl^{-}(aq)+H_{2}O(l)\), we can observe that \(Na^{+}\) and \(Cl^{-}\) ions appear on both sides of the equation. This means they do not undergo any chemical change during the reaction, fulfilling the definition of spectator ions.

To write the net - ionic equation, we remove the spectator ions (\(Na^{+}\) and \(Cl^{-}\)) from the total ionic equation. The remaining ions (\(H^{+}\) and \(OH^{-}\)) react to form water.

Answer:

Yes

For the net - ionic equation: