Question

multiplying and dividing monomials - item 7637
question
which is equivalent to $(-m)^4 \cdot n^2$?
options:
$m^4n^2$
$-(m^4n^2)$
$mn^8$
$-mn^8$

Explanation:

Step1: Simplify \((-m)^4\)

Using the power of a product rule \((ab)^n = a^n b^n\), here \(a=-1\) and \(b = m\), so \((-m)^4=(-1)^4\cdot m^4\). Since \((-1)^4 = 1\), this simplifies to \(m^4\).

Step2: Multiply by \(n^2\)

Now we have \(m^4\cdot n^2\), which is \(m^4n^2\).

Answer:

\(m^4n^2\) (corresponding to the option "A. \(m^4n^2\)" assuming the first option is labeled A)