Question

multiply the special product. (\\(\sqrt{5}+6\\))² = □

Explanation:

Step1: Apply perfect - square formula

Use the formula $(a + b)^2=a^{2}+2ab + b^{2}$, where $a = \sqrt{5}$ and $b = 6$.
$(\sqrt{5}+6)^{2}=(\sqrt{5})^{2}+2\times\sqrt{5}\times6+6^{2}$

Step2: Calculate each term

$(\sqrt{5})^{2}=5$, $2\times\sqrt{5}\times6 = 12\sqrt{5}$, and $6^{2}=36$.
$(\sqrt{5})^{2}+2\times\sqrt{5}\times6+6^{2}=5 + 12\sqrt{5}+36$

Step3: Combine like - terms

$5 + 12\sqrt{5}+36=41 + 12\sqrt{5}$

Answer:

$41+12\sqrt{5}$