Question

do the multiplication.

1. \\((-3) \times 5 = \underline{\quad}\\)
2. \\((-7) \times (-8) = \underline{\quad}\\)
3. \\(6 \times (-12) = \underline{\quad}\\)
4. \\(6 \times (-4) = \underline{\quad}\\)
5. \\((-9) \times (-5) = \underline{\quad}\\)
6. \\((-10) \times 7 = \underline{\quad}\\)
7. \\((-8) \times 2 \times (-3) = \underline{\quad}\\)
8. \\((-4) \times (-2) \times (-8) = \underline{\quad}\\)
9. \\(9 \times (-3) \times (-1) = \underline{\quad}\\)
10. \\(3 \times 4 \times (-9) = \underline{\quad}\\)

fill in the missing integers.

1. \\(9 \times \underline{\quad} = -45\\)
2. \\(\underline{\quad} \times (-3) = 15\\)
3. \\(\underline{\quad} \times (-6) = -36\\)
4. \\(8 \times \underline{\quad} = -16\\)
5. \\((-5) \times (-2) \times \underline{\quad} = -40\\)
6. \\(\underline{\quad} \times 7 \times (-3) = 42\\)

Explanation:

Multiply two integers with different signs

When multiplying a positive integer and a negative integer, the product is always negative.
For question 17:

$$ (-3) \times 5 = -15 $$

For question 19:

$$ 6 \times (-12) = -72 $$

For question 20:

$$ 6 \times (-4) = -24 $$

For question 22:

$$ (-10) \times 7 = -70 $$

Multiply two integers with the same sign

When multiplying two negative integers, the product is always positive.
For question 18:

$$ (-7) \times (-8) = 56 $$

For question 21:

$$ (-9) \times (-5) = 45 $$

Multiply three integers step-by-step

Multiply the first two numbers, then multiply the result by the third number.
For question 23:

$$ (-8) \times 2 \times (-3) = (-16) \times (-3) = 48 $$

For question 24:

$$ (-4) \times (-2) \times (-8) = 8 \times (-8) = -64 $$

For question 25:

$$ 9 \times (-3) \times (-1) = (-27) \times (-1) = 27 $$

For question 26:

$$ 3 \times 4 \times (-9) = 12 \times (-9) = -108 $$

Find the missing integer in two-factor equations

Determine the missing value by dividing the product by the known factor.
For question 27:

$$ 9 \times \underline{\quad} = -45 \implies \frac{-45}{9} = -5 $$

For question 28:

$$ \underline{\quad} \times (-3) = 15 \implies \frac{15}{-3} = -5 $$

For question 29:

$$ \underline{\quad} \times (-6) = -36 \implies \frac{-36}{-6} = 6 $$

For question 30:

$$ 8 \times \underline{\quad} = -16 \implies \frac{-16}{8} = -2 $$

Find the missing integer in three-factor equations

First, multiply the known factors, then divide the product by that result.
For question 31:

$$ (-5) \times (-2) \times \underline{\quad} = -40 \implies 10 \times \underline{\quad} = -40 \implies \frac{-40}{10} = -4 $$

For question 32:

$$ \underline{\quad} \times 7 \times (-3) = 42 \implies \underline{\quad} \times (-21) = 42 \implies \frac{42}{-21} = -2 $$

Answer:

No.	Problem	Answer
18	\( (-7) \times (-8) = \)	\(56\)
19	\( 6 \times (-12) = \)	\(-72\)
20	\( 6 \times (-4) = \)	\(-24\)
21	\( (-9) \times (-5) = \)	\(45\)
22	\( (-10) \times 7 = \)	\(-70\)
23	\( (-8) \times 2 \times (-3) = \)	\(48\)
24	\( (-4) \times (-2) \times (-8) = \)	\(-64\)
25	\( 9 \times (-3) \times (-1) = \)	\(27\)
26	\( 3 \times 4 \times (-9) = \)	\(-108\)
27	\( 9 \times \underline{\quad} = -45 \)	\(-5\)
28	\( \underline{\quad} \times (-3) = 15 \)	\(-5\)
29	\( \underline{\quad} \times (-6) = -36 \)	\(6\)
30	\( 8 \times \underline{\quad} = -16 \)	\(-2\)
31	\( (-5) \times (-2) \times \underline{\quad} = -40 \)	\(-4\)
32	\( \underline{\quad} \times 7 \times (-3) = 42 \)	\(-2\)