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Question
multiple-choice question if $r^2 = 9$, what is $r=$? 9 3 81 rewatch graph the circle. equation. a. $(x + 3)^2 + (y - 2)^2 = 9$ $(x - h)^2 + (y - k)^2 = r^2$ center: $(-3, 2)$ radius = b. $(x + 4)^2 + (y - 8)^2 = 36$
Step1: Recall the square root property
To find \( R \) when \( R^2 = 9 \), we use the square root property. For a non - negative real number \( a \), if \( x^2=a \), then \( x = \pm\sqrt{a} \). Since \( R \) represents a radius (a non - negative quantity), we consider the positive square root.
Step2: Calculate the square root of 9
We know that \( \sqrt{9}=3 \) because \( 3\times3 = 9 \). So if \( R^2 = 9 \), then \( R=\sqrt{9}=3 \) (we take the positive value as radius is non - negative).
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