Question

multiple choice question
a spring scale is used to exert a constant force of 5.0 n east on test mass of 1.4 kg. what is its acceleration?
o 3.6 m/s² west
o 3.6 m/s² east
o 0.28 m/s² west
o 0.28 m/s² east
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Explanation:

Step1: Apply Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the force, \(m\) is the mass, and \(a\) is the acceleration. We need to solve for \(a\), so the formula becomes \(a=\frac{F}{m}\).

Step2: Substitute the given values

Given \(F = 5.0\ N\) (east) and \(m=1.4\ kg\). Substitute into \(a=\frac{F}{m}\), we get \(a=\frac{5.0\ N}{1.4\ kg}\approx3.6\ m/s^{2}\). The direction of the acceleration is the same as the direction of the force, which is east.

Answer:

3.6 m/s² east