Question

multiple choice 2 points
name the following compounds systematically.
(i): 1 - methylcycloocta - 1,4,6 - triene
(ii): 3 - bromo - 4 - methylcyclopent - 1 - ene
(i): 6 - methylcycloocta - 1,3,5 - triene
(ii): 3 - bromo - 2 - methylcyclopent - 1 - ene
(i): 4 - methylcycloocta - 1,4,6 - triene
(ii): 3 - bromo - 4 - methylcyclopent - 1 - ene
(i): 1 - methylcycloocta - 1,3,5 - triene
(ii): 4 - bromo - 3 - methylcyclopent - 1 - ene

Explanation:

Step1: Naming compound (i)

For cyclic compounds with multiple double bonds (triene), numbering starts at the substituent (methyl). Double bonds are at positions 1,4,6. So, 1 - methylcycloocta - 1,4,6 - triene.

Step2: Naming compound (ii)

For the cyclopentene (five - membered ring with one double bond), numbering starts at the double bond. Bromine is at position 3 and methyl at 4. So, 3 - bromo - 4 - methylcyclopent - 1 - ene.

Answer:

A. (i): 1 - methylcycloocta - 1,4,6 - triene (ii): 3 - bromo - 4 - methylcyclopent - 1 - ene