Question

4 multiple choice 1 point
calculate the atomic mass of silver sulfate, ag₂so₄.
311.86 amu
300.80 amu
310.10 amu
380.11 amu
clear my selection
5 multiple choice 1 point
how many chlorine atoms are in a molecule of chloroform, chcl₃?
1
3
6
2
clear my selection

Explanation:

Question 4

Step1: Recall atomic masses

Atomic mass of Ag: \(107.87\) amu, S: \(32.07\) amu, O: \(16.00\) amu.

Step2: Calculate for \(Ag_2SO_4\)

For Ag: \(2\times107.87 = 215.74\) amu.
For S: \(1\times32.07 = 32.07\) amu.
For O: \(4\times16.00 = 64.00\) amu.
Total: \(215.74 + 32.07 + 64.00 = 311.81\) (close to 311.86 amu).

The formula of chloroform is \(CHCl_3\). The subscript of Cl is 3, so each molecule has 3 Cl atoms.

Answer:

311.86 amu (the first option)

Question 5