Question

5 multiple choice 10 points what is the formula for mercury (i) phosphide? hg3p hg3po3 hg3po4 hgp

Explanation:

Step1: Determine the charge of mercury (I) ion

Mercury (I) ion is \(Hg_2^{2 +}\), which can be considered as having an equivalent charge of \(+ 1\) per \(Hg\) in terms of formula - writing (since \(Hg_2^{2+}\) dissociates in a way relevant to ionic compound formation).

Step2: Determine the charge of phosphide ion

Phosphide ion is \(P^{3 -}\).

Step3: Use the criss - cross method

To form a neutral compound, for the charges \(+1\) (from \(Hg\) in the equivalent sense) and \(-3\) (from \(P\)), we need \(3\) \(Hg\) (from \(Hg_2^{2+}\), but in formula - writing, we use the ratio based on charge balance) and \(1\) \(P\). So the formula is \(Hg_3P\).

Answer:

\(Hg_3P\) (the first option)