Question

mr.
physics period
full name
date
laberstory #9: kinematics project
ex: last week, my alarm didnt go off and i realized that i was going to be late to mr. onokojis physics class. knowing that his class was only 5000 meters away, i jumped on my tricycle and drove there as fast as i could. when i got to his class, my smart phone displayed a final velocity of 345 m/s. assuming that i started from rest, what was my acceleration during the entire ordeal?

1. create a problem that uses formula #1: (name)

Explanation:

Step1: Identify the formula

The formula \(v^{2}=(v_{i})^{2}+2ad\) is used when we know the initial velocity (\(v_{i}\)), the final velocity (\(v\)), and the displacement (\(d\)) and we want to find the acceleration (\(a\)).

Step2: Substitute the values

We are given that \(v = 345\ m/s\), \(v_{i}=0\ m/s\) (started from rest), and \(d = 5000\ m\).
Substitute these values into the formula \(v^{2}=(v_{i})^{2}+2ad\).
So, \((345)^{2}=(0)^{2}+2a\times5000\).

Step3: Solve for \(a\)

First, simplify the left - hand side: \(345^{2}=119025\).
The equation becomes \(119025 = 0+10000a\).
To solve for \(a\), divide both sides of the equation by \(10000\): \(a=\frac{119025}{10000}=11.9025\ m/s^{2}\).

Answer:

The acceleration during the order (assuming the values are correct as per the problem description) is \(11.9025\ m/s^{2}\).