Question

1. mr. coffman asked his students to write an example of a square root with a value greater than 11 but less than 11.5. circle the name of any student who correctly completed the task.

fabio
\\( \sqrt { 1 1 9 } \\)
dean
\\( \sqrt { 1 2 2 } \\)
edison
\\( \sqrt { 1 4 1 } \\)
candace
\\( \sqrt { 1 3 0 } \\)

Explanation:

Step1: Calculate the value of each square root

• For \(\sqrt{119}\):

Since \(10^2 = 100\) and \(11^2=121\), \(\sqrt{100}<\sqrt{119}<\sqrt{121}\), so \(10 < \sqrt{119}<11\).

• For \(\sqrt{122}\):

Since \(11^2 = 121\) and \(12^2=144\), \(\sqrt{121}<\sqrt{122}<\sqrt{144}\), so \(11 < \sqrt{122}\approx11.045\).

• For \(\sqrt{141}\):

Since \(11^2 = 121\) and \(12^2=144\), \(\sqrt{121}<\sqrt{141}<\sqrt{144}\), so \(11 < \sqrt{141}\approx11.874\).

• For \(\sqrt{130}\):

Since \(11^2 = 121\) and \(12^2=144\), \(\sqrt{121}<\sqrt{130}<\sqrt{144}\), so \(11 < \sqrt{130}\approx11.402\).

Step2: Check the condition

We need a value greater than \(11\) but less than \(11.5\).
\(\sqrt{122}\approx11.045\) (does not satisfy \(> 11\) enough in the range), \(\sqrt{141}\approx11.874>11.5\), \(\sqrt{130}\approx11.402\) satisfies \(11 < 11.402<11.5\).

Answer:

CANDACE