Question

the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depe evaluate $3x^2 - 2xy - 4y^2$ when $x = 2$ and $y = -3$. \bigcirc 12 \bigcirc 36 \bigcirc -36 \bigcirc -12

Explanation:

Step1: Substitute \(x = 2\) and \(y=-3\) into the expression.

We have the expression \(3x^{2}-2xy - 4y^{2}\). Substitute \(x = 2\) and \(y=-3\) into each term:

• For the term \(3x^{2}\): \(3\times(2)^{2}=3\times4 = 12\)
• For the term \(-2xy\): \(-2\times(2)\times(-3)=12\) (because multiplying two negative numbers gives a positive number, and \(2\times3 = 6\), then \( - 2\times2\times(-3)=12\))
• For the term \(-4y^{2}\): \(-4\times(-3)^{2}=-4\times9=-36\) (since \((-3)^{2}=9\))

Step2: Combine the results of each term.

Now, add the three terms together: \(12 + 12-36\). First, \(12+12 = 24\), then \(24-36=-12\).

Answer:

\(-12\) (corresponding to the option "−12")