Question

the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on you
solve the following and graph the solutions:
$2x + 5 > -9$ or $-3x + 2 < 14$
$x > -7$ or $x > -4$
(option with two open circles at -7 and -4, left arrow from -7, right arrow from -4)
$x > -7$ or $x < -4$
(option with two ticks at -7 and -4, full line arrow both ways)
$x > -7$ or $x < -4$
(option with two open circles at -7 and -4, left arrow from -7, right arrow from -4)
$x > -7$ or $x > -4$
(option with open circle at -7, right arrow, tick at -4)

Explanation:

Step1: Solve \(2x + 5 > -9\)

Subtract 5 from both sides: \(2x + 5 - 5 > -9 - 5\) → \(2x > -14\).
Divide by 2: \(\frac{2x}{2} > \frac{-14}{2}\) → \(x > -7\).

Step2: Solve \(-3x + 2 < 14\)

Subtract 2 from both sides: \(-3x + 2 - 2 < 14 - 2\) → \(-3x < 12\).
Divide by \(-3\) (reverse inequality): \(\frac{-3x}{-3} > \frac{12}{-3}\) → \(x > -4\).

Step3: Analyze "or" compound inequality

For \(x > -7\) or \(x > -4\), the solution is \(x > -7\) (since \(x > -4\) is a subset of \(x > -7\)).

Step4: Match the graph

The last graph has an open circle at \(-7\) and a line extending to the right (covering \(x > -7\)), which matches \(x > -7\) (equivalent to \(x > -7\) or \(x > -4\)).

Answer:

The last graph (with open circle at \(-7\) and line to the right)