Question

the molar mass of nh3 is 17.04 g/mol. what is the percent h in nh3? (h = 1.01 g/mol, n = 14.01 amu) note there are 3 h atoms in the compound. % comp. h = \frac{mass h}{mass of sample} × 100 ?% h

Explanation:

Step1: Calculate the mass of H in \(NH_3\)

Since there are 3 H atoms in \(NH_3\) and the molar mass of H is \(1.01\ g/mol\), the mass of H is \(3\times1.01 = 3.03\ g/mol\).

Step2: Calculate the percent of H

Using the formula \(\% \text{comp. H}=\frac{\text{mass H}}{\text{mass of sample}}\times 100\), substitute the values. The mass of the sample (molar mass of \(NH_3\)) is \(17.04\ g/mol\). So \(\% \text{comp. H}=\frac{3.03}{17.04}\times 100\).

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Answer:

\(17.8\%\)