Question

module 4 review-transformations and symm
ue tuesday by 11:59pm points 25 submitting an external tool
question 2 module 4 review-transformations and symmet
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when point f is reflected in y = x, the image is located at f (6, -9).
point f is located at ( )

Explanation:

Step1: Recall reflection rule

When reflecting a point \((x,y)\) over the line \(y = x\), the rule is \((x,y)\to(y,x)\).

Step2: Apply the rule

Let the original point \(F\) be \((a,b)\). After reflection over \(y = x\), it becomes \(F'(b,a)\). Given \(F'(6,-9)\), then \(a=-9\) and \(b = 6\).

Answer:

\((-9,6)\)