Question

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part a
what volume is occupied by 0.102 mol of helium gas at a pressure of 0.98 atm and a temperature of 305 k?
express your answer using two significant figures.
view available hint(s)
v = l

Explanation:

Step1: Write the ideal gas law formula

The ideal gas law is \(PV = nRT\), where \(P\) is pressure, \(V\) is volume, \(n\) is the number of moles, \(R\) is the ideal gas constant (\(R=0.0821\space L\cdot atm/(mol\cdot K)\)), and \(T\) is temperature. We need to solve for \(V\), so \(V=\frac{nRT}{P}\).

Step2: Substitute the given values into the formula

Given \(n = 0.102\space mol\), \(P=0.98\space atm\), \(T = 305\space K\), and \(R = 0.0821\space L\cdot atm/(mol\cdot K)\).

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Answer:

\(V = 2.6\space L\)