Question

missed this? watch kcv electron configurations, iwe writing electron configurations from the periodic table read section 9.7. you can click on the review link to access the section in your e text. use the periodic table to write electron configurations for each of the following elements. part a se express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s²2p² should be entered as he2s^22p^2. part b sn express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s²2p² should be entered as he2s^22p^2.

Explanation:

Step1: Determine the atomic number of Se

Selenium (Se) has an atomic number of 34.

Step2: Find the noble gas core

The noble gas before Se is Ar (atomic number 18).

Step3: Fill the remaining electrons

After [Ar], we have 34 - 18 = 16 electrons. The electron - filling order is \(4s\), \(3d\), \(4p\). The \(4s\) orbital can hold 2 electrons, the \(3d\) orbital can hold 10 electrons, and the \(4p\) orbital can hold 6 electrons. But we have 16 electrons. So, \(4s^{2}3d^{10}4p^{4}\)

Step1: Determine the atomic number of Sn

Tin (Sn) has an atomic number of 50.

Step2: Find the noble gas core

The noble gas before Sn is Kr (atomic number 36).

Step3: Fill the remaining electrons

After [Kr], we have 50 - 36 = 14 electrons. The electron - filling order is \(5s\), \(4d\), \(5p\). The \(5s\) orbital can hold 2 electrons, the \(4d\) orbital can hold 10 electrons, and we have 14-(2 + 10)=2 electrons left for the \(5p\) orbital. So, \(5s^{2}4d^{10}5p^{2}\)

Answer:

[Ar]4s^23d^104p^4