Question

miss diaz wants her students to practice making the next ten.
a. circle the problems miss diaz should give her students.
12 + 23 38 + 22 64 + 99 36 + 40 79 + 48
b. explain why miss diaz should give the problems you circled.

Explanation:

Step1: Understand "making the next ten"

"Making the next ten" means using addition strategies to reach the next multiple of ten. For example, if we have a number like \(38\), we can add \(2\) to make \(40\) (a multiple of ten).

Step2: Analyze each problem

• For \(12 + 23\): \(12+23=(10 + 2)+(20+3)=30 + 5=35\). No strategy of making the next ten is obvious here.
• For \(38+22\): \(38+22=(38 + 2)+20=40+20 = 60\). We can break \(22\) into \(2\) and \(20\) to make \(38+2 = 40\) (the next ten).
• For \(64+99\): \(64+99=64+(100 - 1)=164-1 = 163\). We can think of \(99\) as \(100-1\), and \(64 + 100=164\) (a multiple of ten is not directly made in the first - step addition).
• For \(36+40\): \(36+40 = 76\). No strategy of making the next ten is involved in a non - trivial way.
• For \(79+48\): \(79+48=(79 + 1)+47=80+47 = 127\). We can break \(48\) into \(1\) and \(47\) to make \(79 + 1=80\) (the next ten).

Answer:

a. Circle \(38 + 22\) and \(79+48\).
b. For \(38 + 22\), we can break \(22\) into \(2\) and \(20\). First, \(38+2 = 40\) (making the next ten: \(40\)) and then \(40+20=60\). For \(79+48\), we can break \(48\) into \(1\) and \(47\). First, \(79 + 1=80\) (making the next ten: \(80\)) and then \(80+47 = 127\). These problems allow students to practice the "making the next ten" addition strategy.