QUESTION IMAGE
Question
if c, p, and t are the midpoints of the sides of \\( \triangle aen, pt = 13, en = 43 \\), and \\( cp = 29 \\), find each measure.
- \\( ae = \\)
- \\( an = \\)
- \\( ct = \\)
- perimeter of \\( \triangle aen = \\)
Step1: Use the mid - segment theorem
The mid - segment theorem states that the segment connecting the midpoints of two sides of a triangle is parallel to the third side and half its length.
Since \(C\) and \(P\) are midpoints of \(AE\) and \(EN\) respectively, \(CP\parallel AN\) and \(CP=\frac{1}{2}AN\).
Given \(CP = 29\), then \(AN=2\times CP\).
\(AN = 2\times29=58\)
Since \(P\) and \(T\) are midpoints of \(EN\) and \(WN\) respectively, \(PT\parallel AE\) and \(PT=\frac{1}{2}AE\).
Given \(PT = 13\), then \(AE=2\times PT\).
\(AE = 2\times13 = 26\)
Since \(C\) and \(T\) are midpoints of \(AE\) and \(AN\) respectively, \(CT\parallel EN\) and \(CT=\frac{1}{2}EN\).
Given \(EN = 43\), then \(CT=\frac{1}{2}\times43=21.5\)
Step2: Calculate the perimeter of \(\triangle AEN\)
The perimeter of \(\triangle AEN\) is \(P=AE + EN+AN\).
Substitute \(AE = 26\), \(EN = 43\), and \(AN = 58\) into the formula.
\(P=26 + 43+58=127\)
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- \(AE = 26\)
- \(AN = 58\)
- \(CT = 21.5\)
- Perimeter of \(\triangle AEN=127\)