Question

mg + 2hcl → mgcl₂ + h₂ (mg: 24.3 g/mol) the number of moles of gas needed to fill a container was calculated to be 0.16 mol h₂. what mass of mg is required to generate the h₂ gas? ? g mg hint: use stoichiometry. mass mg (g) submit

Explanation:

Step1: Find mole ratio of Mg to H₂

From reaction: 1 mol Mg → 1 mol H₂, so ratio = 1:1

Step2: Calculate moles of Mg

Moles of Mg = moles of H₂ = 0.16 mol

Step3: Compute mass of Mg

Mass = moles × molar mass = 0.16 mol × 24.3 g/mol = 3.888 g ≈ 3.9 g

Answer:

3.9