Question

maya wraps a gift box in the shape of a square pyramid. the figure below shows a net for the gift box. how much wrapping paper did she use, in square inches? answer attempt 1 out of 2 a = in²

Explanation:

Step1: Calculate area of base

The base is a square with side - length $s = 9.6$ inches. The area of a square is $A_{base}=s^{2}$. So, $A_{base}=(9.6)^{2}=92.16$ square inches.

Step2: Calculate area of one triangular face

The base of each triangular face is $b = 9.6$ inches and the height is $h = 10$ inches. The area of a triangle is $A_{triangle}=\frac{1}{2}bh$. So, $A_{triangle}=\frac{1}{2}\times9.6\times10 = 48$ square inches.

Step3: Calculate total area of triangular faces

There are 4 triangular faces. So the total area of the triangular faces is $A_{triangles}=4\times A_{triangle}=4\times48 = 192$ square inches.

Step4: Calculate total surface area

The total surface area $A$ of the square - pyramid (the amount of wrapping paper) is the sum of the area of the base and the area of the triangular faces. So, $A=A_{base}+A_{triangles}=92.16 + 192=284.16$ square inches.

Answer:

$284.16$