Question

1. maverick and goose are flying a training mission in their f - 14. they are flying at an altitude of 1500. m and are traveling at 688 m/s (mach 2). they release their bomb and head for home.

a. how long will it be before the bomb hits the ground?
b. how far (on the ground) from where they released it will it land?
a. 17.5 s
b. 112940 m

Explanation:

Step1: 求炸彈落地時間（A部分）

炸彈在垂直方向做自由落體運動，根據公式 \(h = \frac{1}{2}gt^{2}\)（\(h = 1500m\)，\(g = 9.8m/s^{2}\)），可得 \(t=\sqrt{\frac{2h}{g}}\)。
代入數值 \(t=\sqrt{\frac{2\times1500}{9.8}}\approx17.5s\)。

Step2: 求炸彈水平位移（B部分）

炸彈水平方向做勻速直線運動，水平速度 \(v = 688m/s\)，根據公式 \(x = vt\)。
將 \(v = 688m/s\)，\(t = 17.5s\)代入，可得 \(x=688\times17.5 = 12040m\)。

Answer:

A. \(17.5s\)
B. \(12040m\)