Question

(x² - 9)/(x - 3)

Explanation:

Step1: Factor the numerator

The numerator \(x^2 - 9\) is a difference of squares, which can be factored using the formula \(a^2 - b^2=(a + b)(a - b)\). Here, \(a = x\) and \(b = 3\), so \(x^2 - 9=(x + 3)(x - 3)\).
The expression becomes \(\frac{(x + 3)(x - 3)}{x - 3}\).

Step2: Cancel common factors

Assuming \(x
eq3\) (to avoid division by zero), we can cancel the common factor \((x - 3)\) in the numerator and the denominator.
After canceling, we are left with \(x + 3\).

Answer:

\(x + 3\) (for \(x
eq3\))