Question

$\sqrt3{1728} = \square$

Explanation:

Step1: Factorize 1728

We know that \(1728 = 12\times12\times12\), or in exponent form \(1728 = 12^{3}\).

Step2: Apply cube - root property

The cube - root of a number \(x\) is a number \(y\) such that \(y^{3}=x\). For the cube - root of \(12^{3}\), by the property \(\sqrt[3]{a^{3}}=a\) (where \(a = 12\) in this case), we have \(\sqrt[3]{1728}=\sqrt[3]{12^{3}} = 12\).

Answer:

\(12\)