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Question
solve.
\\\frac{4}{3+z} = \frac{2}{3}\\
Set up the proportion equation
$$
\frac{4}{3+z} = \frac{2}{3}
$$
Apply the cross product property
$$
4 \cdot 3 = 2 \cdot (3 + z)
$$
$$
12 = 6 + 2z
$$
Solve for z
$$
12 - 6 = 2z
$$
$$
6 = 2z
$$
$$
z = 3
$$
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Solve.
$$\frac{4}{3+z} = \frac{2}{3}$$
\(z =\) <blank>\(3\)</blank>