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solve for c. (3(c - 1) = 9) (c = ?)

Question

solve for c.

(3(c - 1) = 9)

(c = ?)

Explanation:

Response

<pre_analysis>
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"needs_drawing": false,
"concepts_used": [
"Distributive Property",
"Linear Equations",
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</pre_analysis>

<reasoning>

Distribute the constant factor

Using the Distributive Property and Linear Equations knowledge points
\[

$$\begin{aligned} 3(c - 1) &= 9 \\ 3c - 3 &= 9 \end{aligned}$$

\]

Isolate the variable term

Using the One-Step Equations and Linear Equations knowledge points
\[

$$\begin{aligned} 3c - 3 + 3 &= 9 + 3 \\ 3c &= 12 \end{aligned}$$

\]

Solve for c

Using the One-Step Equations and Linear Equations knowledge points
\[

$$\begin{aligned} \frac{3c}{3} &= \frac{12}{3} \\ c &= 4 \end{aligned}$$

\]
</reasoning>

<answer>
Solve for c.

\(3(c - 1) = 9\)

\(c =\) <blank>4</blank>
</answer>

<post_analysis>
{
"subject": "Mathematics",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Linear Equations"
]
}
</post_analysis>

Answer:

<pre_analysis>
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"step_cot",
"blank_filling_formatter",
"explain_then_answer",
"tutor",
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],
"needs_drawing": false,
"concepts_used": [
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],
"new_concepts": [],
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"Linear Equations",
"One-Step Equations"
]
}
</pre_analysis>

<reasoning>

Distribute the constant factor

Using the Distributive Property and Linear Equations knowledge points
\[

$$\begin{aligned} 3(c - 1) &= 9 \\ 3c - 3 &= 9 \end{aligned}$$

\]

Isolate the variable term

Using the One-Step Equations and Linear Equations knowledge points
\[

$$\begin{aligned} 3c - 3 + 3 &= 9 + 3 \\ 3c &= 12 \end{aligned}$$

\]

Solve for c

Using the One-Step Equations and Linear Equations knowledge points
\[

$$\begin{aligned} \frac{3c}{3} &= \frac{12}{3} \\ c &= 4 \end{aligned}$$

\]
</reasoning>

<answer>
Solve for c.

\(3(c - 1) = 9\)

\(c =\) <blank>4</blank>
</answer>

<post_analysis>
{
"subject": "Mathematics",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Linear Equations"
]
}
</post_analysis>