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solve for b. \\frac{5b + 1}{3} = 7 b = ?

Question

solve for b.
\frac{5b + 1}{3} = 7
b = ?

Explanation:

Step1: Eliminate the denominator

Multiply both sides of the equation $\frac{5b + 1}{3}=7$ by 3 to get rid of the denominator. So we have $3\times\frac{5b + 1}{3}=3\times7$, which simplifies to $5b + 1 = 21$.

Step2: Isolate the term with b

Subtract 1 from both sides of the equation $5b + 1 = 21$. That gives $5b+1 - 1=21 - 1$, so $5b = 20$.

Step3: Solve for b

Divide both sides of the equation $5b = 20$ by 5. We get $\frac{5b}{5}=\frac{20}{5}$, which simplifies to $b = 4$.

Answer:

$b = 4$