QUESTION IMAGE
Question
solve for a.
$a^2 = 144$
$a = \boxed{}$ or $\boxed{}$
Step1: Take square root of both sides
To solve for \( a \) when \( a^2 = 144 \), we take the square root of both sides. The square root of a number \( x^2 \) is \( \pm x \) because both \( x \) and \( -x \) squared give \( x^2 \). So, \( \sqrt{a^2}=\pm\sqrt{144} \).
Step2: Simplify the square roots
We know that \( \sqrt{a^2}=|a| \), but since we are solving for \( a \) in a simple quadratic equation, we can directly find that \( \sqrt{144} = 12 \) (because \( 12\times12 = 144 \)) and \( \sqrt{144}=- 12 \) (because \( (-12)\times(-12)=144 \)). So, \( a=\pm12 \).
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\( 12 \) or \( -12 \)