Question

$\log_{5}47$

Explanation:

Step1: Recall the change - of - base formula

The change - of - base formula for logarithms is $\log_{a}b=\frac{\ln b}{\ln a}$. So, $\log_{5}47 = \frac{\ln47}{\ln5}$.

Step2: Use a calculator to find the values

We know that $\ln47\approx3.850147$ and $\ln5\approx1.609438$.
Then $\frac{\ln47}{\ln5}=\frac{3.850147}{1.609438}\approx2.392$.

Answer:

$\approx2.392$