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$\\frac{19}{42} + \\frac{1}{6} = \\frac{\\square}{\\square}$

Question

$\frac{19}{42} + \frac{1}{6} = \frac{\square}{\square}$

Explanation:

Step1: Find a common denominator

The denominators are 42 and 6. The least common denominator is 42. Rewrite $\frac{1}{6}$ with denominator 42: $\frac{1}{6}=\frac{1\times7}{6\times7}=\frac{7}{42}$

Step2: Add the fractions

Now add $\frac{19}{42}$ and $\frac{7}{42}$: $\frac{19 + 7}{42}=\frac{26}{42}$

Step3: Simplify the fraction

Divide numerator and denominator by their greatest common divisor, which is 2: $\frac{26\div2}{42\div2}=\frac{13}{21}$

Answer:

$\frac{13}{21}$