find $(-2r - 3)(5r - 1)(r + 4)$.

Question

Accepted Answer

# Explanation:
## Step1: Multiply the first two binomials
First, multiply $(-2r - 3)$ and $(5r - 1)$ using the distributive property (FOIL method):
$$
\begin{align*}
(-2r - 3)(5r - 1)&=-2r\times5r+(-2r)\times(-1)+(-3)\times5r+(-3)\times(-1)\
&=-10r^{2}+2r - 15r + 3\
&=-10r^{2}-13r + 3
\end{align*}
$$
## Step2: Multiply the result by the third binomial
Now, multiply $(-10r^{2}-13r + 3)$ by $(r + 4)$:
$$
\begin{align*}
(-10r^{2}-13r + 3)(r + 4)&=-10r^{2}\times r+(-10r^{2})\times4+(-13r)\times r+(-13r)\times4+3\times r+3\times4\
&=-10r^{3}-40r^{2}-13r^{2}-52r + 3r + 12\
&=-10r^{3}+(-40r^{2}-13r^{2})+(-52r + 3r)+12\
&=-10r^{3}-53r^{2}-49r + 12
\end{align*}
$$
# Answer:
$-10r^{3}-53r^{2}-49r + 12$

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QUESTION IMAGE

Question

Explanation:

Step1: Multiply the first two binomials

Step2: Multiply the result by the third binomial

Answer: