Question

c) $\frac{3k}{5}-6=\frac{k}{3}$

Explanation:

Step1: Move terms with k to one - side

Subtract $\frac{k}{3}$ from both sides and add 6 to both sides: $\frac{3k}{5}-\frac{k}{3}=6$.

Step2: Find a common denominator

The common denominator of 5 and 3 is 15. Rewrite the left - hand side: $\frac{3k\times3}{5\times3}-\frac{k\times5}{3\times5}=6$, which simplifies to $\frac{9k}{15}-\frac{5k}{15}=6$.

Step3: Combine like terms

$\frac{9k - 5k}{15}=6$, so $\frac{4k}{15}=6$.

Step4: Solve for k

Multiply both sides by 15 to get $4k = 6\times15=90$. Then divide both sides by 4, so $k=\frac{90}{4}=\frac{45}{2}=22.5$.

Answer:

$k = 22.5$