Question

($c^2 - 9c + 7$) + ($-5c + 8$)

Explanation:

Step1: Remove parentheses

We have the expression \((c^{2}-9c + 7)+(-5c + 8)\). When we remove the parentheses, the signs of the terms inside the second parentheses are adjusted according to the plus sign in front. So it becomes \(c^{2}-9c + 7-5c + 8\).

Step2: Combine like terms

For the \(c\) terms: \(-9c-5c=-14c\). For the constant terms: \(7 + 8 = 15\). The \(c^{2}\) term remains as it is since there is no other \(c^{2}\) term to combine with. So combining like terms gives us \(c^{2}-14c + 15\).

Answer:

\(c^{2}-14c + 15\)