Question

1. \frac{1}{8}(p + 24) = 9\

\boxed{} + \boxed{} = \boxed{}\
p = \boxed{}

Explanation:

Step1: Apply Distributive Property

We start with the equation $\frac{1}{8}(p + 24)=9$. Using the distributive property $a(b + c)=ab+ac$, we get $\frac{1}{8}p+\frac{1}{8}\times24 = 9$. Calculating $\frac{1}{8}\times24$, we have $\frac{24}{8}=3$. So the equation becomes $\frac{1}{8}p + 3=9$.

Step2: Subtract 3 from Both Sides

Subtract 3 from both sides of the equation $\frac{1}{8}p + 3=9$. So we have $\frac{1}{8}p+3 - 3=9 - 3$, which simplifies to $\frac{1}{8}p=6$.

Step3: Solve for p

Multiply both sides of the equation $\frac{1}{8}p = 6$ by 8 to isolate $p$. So $8\times\frac{1}{8}p=6\times8$, which gives $p = 48$.

Answer:

The first box (after distributive property) is $\frac{1}{8}p$, the second box is $3$, the third box (after subtraction) is $6$, and $p = 48$.