Question

5^{\log_{5} x}

Explanation:

Step 1: Recall the logarithm power rule

The power rule of logarithms states that \(a^{\log_{a}b}=b\) for \(a>0,a
eq1\) and \(b > 0\).

Step 2: Apply the rule to the given expression

In the expression \(5^{\log_{5}x}\), we have \(a = 5\) and \(b=x\). By applying the power rule of logarithms \(a^{\log_{a}b}=b\), we get \(5^{\log_{5}x}=x\) (assuming \(x>0\) since the logarithm \(\log_{5}x\) is defined for \(x > 0\)).

Answer:

\(x\) (for \(x>0\))