Question

5.

$$ \\lim _ { x \ ightarrow - 1 } \\frac { x + 1 } { x ^ { 2 } + 2 x + 2 } $$

Explanation:

Step1: Substitute \(x = - 1\) into the function

Substitute \(x=-1\) into \(\frac{x + 1}{x^{2}+2x + 2}\).
For the numerator: \(x + 1=-1 + 1=0\).
For the denominator: \(x^{2}+2x + 2=(-1)^{2}+2\times(-1)+2=1-2 + 2=1\).

Answer:

\(0\)