Question

1. $\frac{-6}{7} \leq \frac{3}{7}f$

Explanation:

Step1: Multiply both sides by 7

To eliminate the denominators, we multiply each term in the inequality \(-\frac{6}{7} \leq \frac{3}{7}f\) by 7. This gives us \(-6 \leq 3f\).

Step2: Divide both sides by 3

Now, we divide both sides of the inequality \(-6 \leq 3f\) by 3 to solve for \(f\). So, \(\frac{-6}{3} \leq \frac{3f}{3}\), which simplifies to \(-2 \leq f\) or \(f \geq -2\).

Answer:

\(f \geq -2\) (On the number line, this would be a closed circle at -2 and an arrow pointing to the right.)