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3. $9 > y + \\frac{3}{4}$

Question

  1. $9 > y + \frac{3}{4}$

Explanation:

Step1: Subtract 3/4 from both sides

To solve the inequality \( 9 > y + \frac{3}{4} \), we subtract \( \frac{3}{4} \) from both sides. This gives us \( 9 - \frac{3}{4} > y \).

Step2: Calculate 9 - 3/4

We convert 9 to a fraction with denominator 4: \( 9 = \frac{36}{4} \). Then, \( \frac{36}{4} - \frac{3}{4} = \frac{33}{4} = 8\frac{1}{4} \). So the solution is \( y < 8\frac{1}{4} \).

Answer:

\( y < 8\frac{1}{4} \) (To graph this, we would draw an open circle at \( 8\frac{1}{4} \) on the number line and shade to the left.)