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Question
- \\(28n^4 + 16n^3 - 80n^2\\)
Identify the terms
We start with the polynomial:
$$28n^4 + 16n^3 - 80n^2$$
Find the GCF of coefficients
Find the greatest common factor of \(28\), \(16\), and \(-80\).
The factors of each are:
- \(28 = 4 \times 7\)
- \(16 = 4 \times 4\)
- \(-80 = 4 \times (-20)\)
The greatest common numerical factor is \(4\).
Find the GCF of variables
Find the lowest power of \(n\) in the terms:
- \(n^4\)
- \(n^3\)
- \(n^2\)
The lowest power is \(n^2\).
Factor out the GCF
Combine the GCF of coefficients and variables:
$$\text{GCF} = 4n^2$$
Divide each term by \(4n^2\):
- \(\frac{28n^4}{4n^2} = 7n^2\)
- \(\frac{16n^3}{4n^2} = 4n\)
- \(\frac{-80n^2}{4n^2} = -20\)
Write the factored expression
Combine the GCF and the remaining terms:
$$4n^2(7n^2 + 4n - 20)$$
The quadratic inside cannot be factored further over the integers.
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\(4n^2(7n^2 + 4n - 20)\)