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match the addition and subtraction problems to their solutions: 1/24, 2…

Question

match the addition and subtraction problems to their solutions: 1/24, 2/7, 2/3, 7/10, 3/4; 5/7 - 3/7; 1/6 + 3/6; 1/2 + 1/4; 1/5 + 1/2; 1/6 - 1/8

Explanation:

Step1: Solve $\frac{5}{7} - \frac{3}{7}$

Subtract numerators: $\frac{5 - 3}{7} = \frac{2}{7}$

Step2: Solve $\frac{1}{6} + \frac{3}{6}$

Add numerators: $\frac{1 + 3}{6} = \frac{4}{6} = \frac{2}{3}$ (simplify by dividing numerator and denominator by 2)

Step3: Solve $\frac{1}{2} + \frac{1}{4}$

Find common denominator (4): $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$

Step4: Solve $\frac{1}{5} + \frac{1}{2}$

Find common denominator (10): $\frac{2}{10} + \frac{5}{10} = \frac{7}{10}$

Step5: Solve $\frac{1}{6} - \frac{1}{8}$

Find common denominator (24): $\frac{4}{24} - \frac{3}{24} = \frac{1}{24}$

Answer:

  • $\frac{5}{7} - \frac{3}{7}$ matches $\frac{2}{7}$
  • $\frac{1}{6} + \frac{3}{6}$ matches $\frac{2}{3}$
  • $\frac{1}{2} + \frac{1}{4}$ matches $\frac{3}{4}$
  • $\frac{1}{5} + \frac{1}{2}$ matches $\frac{7}{10}$
  • $\frac{1}{6} - \frac{1}{8}$ matches $\frac{1}{24}$