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Question
the ( mangle6=(11x + 8)^{circ} ) and ( mangle7=(12x - 4)^{circ} ) what is the measure of ( angle4 )? ( mangle4 = 40^{circ} ) ( mangle4 = 48^{circ} ) ( mangle4 = 132^{circ} ) ( mangle4 = 140^{circ} )
Step1: Find the value of \(x\)
Since \(\angle6\) and \(\angle7\) are supplementary (they form a linear pair), \(m\angle6 + m\angle7=180^{\circ}\).
So, \((11x + 8)+(12x - 4)=180\).
Combine like - terms: \(11x+12x+8 - 4=180\), \(23x+4 = 180\).
Subtract 4 from both sides: \(23x=180 - 4=176\).
Divide both sides by 23: \(x=\frac{176}{23}\approx8\).
Step2: Calculate \(m\angle6\)
Substitute \(x = 8\) into \(m\angle6=(11x + 8)^{\circ}\).
\(m\angle6=(11\times8 + 8)^{\circ}=(88 + 8)^{\circ}=96^{\circ}\).
Step3: Use the property of parallel lines and transversals
\(\angle4\) and \(\angle6\) are same - side interior angles. But wait, no, \(\angle4\) and \(\angle6\) are not same - side interior. Wait, \(\angle4\) and \(\angle6\) are not the key. Wait, \(\angle6\) and \(\angle7\) are linear pair. After \(x = 8\), \(m\angle7=(12x-4)=(12\times8 - 4)=92^{\circ}\). Wait, no, correction:
Since \(\angle6=(11x + 8)\) and \(\angle7=(12x - 4)\) and \(\angle6+\angle7 = 180\) (linear pair).
\(11x+8+12x - 4=180\), \(23x+4 = 180\), \(23x=176\), \(x = 8\).
\(m\angle6=(11\times8 + 8)=96^{\circ}\), \(m\angle7=(12\times8-4)=92^{\circ}\).
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Step1: Find the value of \(x\)
Since \(\angle6\) and \(\angle7\) are supplementary (they form a linear pair), \(m\angle6 + m\angle7=180^{\circ}\).
So, \((11x + 8)+(12x - 4)=180\).
Combine like - terms: \(11x+12x+8 - 4=180\), \(23x+4 = 180\).
Subtract 4 from both sides: \(23x=180 - 4=176\).
Divide both sides by 23: \(x=\frac{176}{23}\approx8\).
Step2: Calculate \(m\angle6\)
Substitute \(x = 8\) into \(m\angle6=(11x + 8)^{\circ}\).
\(m\angle6=(11\times8 + 8)^{\circ}=(88 + 8)^{\circ}=96^{\circ}\).
Step3: Use the property of parallel lines and transversals
\(\angle4\) and \(\angle6\) are same - side interior angles. But wait, no, \(\angle4\) and \(\angle6\) are not same - side interior. Wait, \(\angle4\) and \(\angle6\) are not the key. Wait, \(\angle6\) and \(\angle7\) are linear pair. After \(x = 8\), \(m\angle7=(12x-4)=(12\times8 - 4)=92^{\circ}\). Wait, no, correction:
Since \(\angle6=(11x + 8)\) and \(\angle7=(12x - 4)\) and \(\angle6+\angle7 = 180\) (linear pair).
\(11x+8+12x - 4=180\), \(23x+4 = 180\), \(23x=176\), \(x = 8\).
\(m\angle6=(11\times8 + 8)=96^{\circ}\), \(m\angle7=(12\times8-4)=92^{\circ}\).
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