Question

1. make a claim about which of the two reactions is successful. describe the evidence and reasoning that supports that claim.

i need a hint
chlorine is capable of replacing iodide in a single replacement reaction. (reaction 1: ki + cl₂ → )
evidence
we observe the formation of purple iodine (i₂) when chlorine is mixed with potassium iodide solution.
we observe the formation of colorless chlorine (cl₂) when iodine is mixed with potassium chloride.

Explanation:

To determine the successful reaction, we analyze the single - replacement reaction principle (more reactive halogen displaces less reactive halogen from its salt). Chlorine ($Cl_2$) is more reactive than iodine ($I_2$). In Reaction 1 ($KI + Cl_2
ightarrow$), when $Cl_2$ reacts with $KI$, the formation of purple $I_2$ is observed. This is because $Cl_2$ (more reactive) displaces $I^-$ from $KI$ to form $I_2$. The second observation (formation of $Cl_2$ when $I_2$ reacts with $KCl$) is incorrect as $I_2$ is less reactive than $Cl_2$ and can't displace $Cl^-$ from $KCl$. So Reaction 1 is successful.

Answer:

Claim: Reaction 1 ($KI + Cl_2
ightarrow$) is successful.
Evidence: We observe the formation of purple iodine ($I_2$) when chlorine is mixed with potassium iodide solution.
Reasoning: In halogen single - replacement reactions, a more reactive halogen displaces a less reactive halogen from its ionic compound. Chlorine is more reactive than iodine. So $Cl_2$ can displace $I^-$ from $KI$ to form $I_2$ (seen as purple), while $I_2$ (less reactive) cannot displace $Cl^-$ from $KCl$, so the second reaction (involving $I_2$ and $KCl$) does not occur as described in the incorrect observation.