Question

magnetic flux and induced emf in a coil
a coil has 200 turns enclosing an area of 11.2 cm². in a physics
laboratory experiment, the coil is rotated during the time interval 0.042 s
from a position in which the plane of each turn is perpendicular to earths
magnetic field to one in which the plane of each turn is parallel to the field.
the magnitude of earths magnetic field at the lab location is 5.40×10⁻⁵ t
part b
what is the magnitude |φ_final| of the magnetic flux through one turn of the coil after it is rotated?
express your answer in webers.
view available hint(s)
|φ_final| =
wb
part c complete previous part(s)

Explanation:

Step1: Recall the formula for magnetic flux

The formula for magnetic flux is $\Phi = BA\cos\theta$, where $B$ is the magnetic field, $A$ is the area, and $\theta$ is the angle between the magnetic field and the normal to the area.

Step2: Determine the values of $B$, $A$, and $\theta$ after rotation

• Given $B = 5.40\times10^{-5}\text{ T}$
• Area $A=11.2\text{ cm}^2=11.2\times10^{-4}\text{ m}^2$ (since $1\text{ cm}^2 = 10^{-4}\text{ m}^2$)
• After rotation, the plane of the coil is parallel to the magnetic field, so $\theta = 90^{\circ}$ and $\cos\theta=\cos90^{\circ}=0$

Step3: Calculate the magnetic flux

Substitute the values into the formula:
$\Phi_{final}=BA\cos\theta=(5.40\times 10^{-5}\text{ T})\times(11.2\times 10^{-4}\text{ m}^2)\times0 = 0\text{ Wb}$

Answer:

$0$