Question

1. a little boy, mass = 40.0 kg, is riding in a wagon pulled by his huge dog, howard. what is the acceleration of the wagon if the dog pulls with a force of 30.0 n? (assume the wagon rolls on a frictionless surface).

Explanation:

Step1: Use Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the force, \(m\) is the mass, and \(a\) is the acceleration. We need to solve for \(a\), so we can rewrite the formula as \(a=\frac{F}{m}\).

Step2: Substitute the given values

We are given that \(F = 30.0\space N\) and \(m=40.0\space kg\). Substituting these values into the formula \(a=\frac{F}{m}\), we get \(a=\frac{30.0}{40.0}\).

Step3: Calculate the acceleration

\(a=\frac{30.0}{40.0}= 0.75\space m/s^{2}\)

Answer:

0.750 m/s²