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QUESTION IMAGE

linear pairs and vertical angles what is the value of x? image of inter…

Question

linear pairs and vertical angles
what is the value of x?
image of intersecting lines with angles (x + 40)° and (3x)° at point r, and four rectangular options with numbers 20, 60, 35, 70 (order as per image)

Explanation:

Step1: Identify Angle Relationship

The angles \((x + 40)^\circ\) and \((3x)^\circ\) are vertical angles? Wait, no, looking at the diagram, actually, \((x + 40)^\circ\) and \((3x)^\circ\) are adjacent and form a linear pair? Wait, no, the lines are intersecting, so vertical angles? Wait, no, let's check again. Wait, the two angles \((x + 40)^\circ\) and \((3x)^\circ\) – wait, maybe they are supplementary? Wait, no, if the lines are intersecting, then adjacent angles on a straight line are supplementary. Wait, actually, the angles \((x + 40)^\circ\) and \((3x)^\circ\) – wait, maybe I made a mistake. Wait, no, looking at the diagram, the two angles \((x + 40)^\circ\) and \((3x)^\circ\) are adjacent and form a linear pair? Wait, no, vertical angles are equal. Wait, maybe the angles \((x + 40)^\circ\) and \((3x)^\circ\) are vertical angles? Wait, no, that can't be. Wait, maybe the lines are such that \((x + 40)^\circ\) and \((3x)^\circ\) are supplementary? Wait, no, let's think again. Wait, the problem is about linear pairs and vertical angles. Wait, maybe the two angles \((x + 40)^\circ\) and \((3x)^\circ\) are vertical angles? No, vertical angles are equal. Wait, maybe I misread. Wait, the diagram: two lines intersecting, so the angles opposite each other are vertical angles. Wait, maybe \((x + 40)^\circ\) and \((3x)^\circ\) are supplementary? Wait, no, if they are adjacent and form a linear pair, then their sum is \(180^\circ\). Wait, let's check the options. The options are 20, 60, 35, 70. Let's assume that \((x + 40) + (3x) = 180\)? Wait, no, maybe they are vertical angles? Wait, no, vertical angles are equal. Wait, maybe the angles \((x + 40)^\circ\) and \((3x)^\circ\) are vertical angles? Then \(x + 40 = 3x\), solving \(40 = 2x\), \(x = 20\). Let's check: \(x + 40 = 60\), \(3x = 60\). Yes, that works. So the angle relationship is vertical angles, so they are equal.

Step2: Set Up Equation

Since the angles are vertical angles, they are equal. So:
\(x + 40 = 3x\)

Step3: Solve for \(x\)

Subtract \(x\) from both sides:
\(40 = 2x\)

Divide both sides by 2:
\(x = 20\)

Answer:

20