Question

the light bulb that lights up the playground at night does 7778 joules of work (energy) every 68 seconds it is turned on. calculate the power.
answer:
check
13
mplete
out of
q
on
what are the units for your answer?
select one:
newtons
inules

Explanation:

Step1: Recall the power formula

Power \( P \) is defined as the work done \( W \) per unit time \( t \), so the formula is \( P=\frac{W}{t} \).

Step2: Identify given values

We know that \( W = 7778 \) Joules and \( t = 68 \) seconds.

Step3: Substitute values into the formula

Substitute \( W = 7778 \) and \( t = 68 \) into \( P=\frac{W}{t} \), we get \( P=\frac{7778}{68} \).

Step4: Calculate the result

\( \frac{7778}{68}=114.38235\cdots\approx114.38 \) (or we can do the division: \( 7778\div68 = 114.3823529\cdots \))

For the units part:

Step1: Recall units of power

The unit of work is Joule (J) and unit of time is second (s). Since \( P=\frac{W}{t} \), the unit of power is Joule per second, which is also called Watt (W).
Newtons are units of force, and Joules are units of work/energy, so the unit of power here should be Watts (or Joules per second).

Answer:

The power is approximately \( 114.38 \) Watts (or using the exact division result as needed). For the units, the correct unit is Watt (Joule per second), so if we assume the options (even though some are cut off, but from context) the unit should be Watt (or the option corresponding to Joule per second, but since the visible wrong options are Newtons and (partially) Joules, the correct unit is Watt (not listed fully but from physics knowledge, power unit is Watt).