Question

li*express your answer in complete form, in order of increasing orbital. for example, 1s^22s^2 would be entered as1s^22s^2.submit request answerpart daiexpress your answer in complete form, in order of increasing orbital. for example, 1s^22s^2 would be entered as1s^22s^2.

Explanation:

Step1: Determine the electron configuration of Li

Li (lithium) has an atomic number of 3. Its electron configuration is \(1s^{2}2s^{1}\).

Step2: Form \(Li^{+}\)

\(Li^{+}\) loses one electron. The electron is lost from the outermost shell (\(2s\)). So the electron configuration of \(Li^{+}\) is \(1s^{2}\), which in the required format is \(1s^{\wedge}2\).

Step3: Determine the electron configuration of Al

Al (aluminum) has an atomic number of 13. Its electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}\).

Step4: Form \(Al^{3 +}\)

\(Al^{3+}\) loses three electrons. The electrons are lost from the outermost shell (\(3s\) and \(3p\)). So the electron configuration of \(Al^{3+}\) is \(1s^{2}2s^{2}2p^{6}\), which in the required format is \(1s^{\wedge}22s^{\wedge}22p^{\wedge}6\).

Answer:

\(1s^{\wedge}2\)
\(1s^{\wedge}22s^{\wedge}22p^{\wedge}6\)